document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=576749>Question 576749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of a radioactive substance is the time it takes for half of the substance to decay. The half-life if carbon-14 is 5700 years.\r<BR>\n" );
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document.write( "A.) write a exponential function to model the decay of a 240-my sample.\r<BR>\n" );
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document.write( "B.) explain what each value in the function model represents.\r<BR>\n" );
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document.write( "C.) to the nearest hundredth, find the amount of carbon-14 remaining after 2353 years. Explain how you found this amount. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370013 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The half-life of a radioactive substance is the time it takes for half of the substance to decay.<BR>\n" );
document.write( "The half-life if carbon-14 is 5700 years.<BR>\n" );
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document.write( "The radioactive decay formula: A = Ao*2^(-t/h)<BR>\n" );
document.write( "where<BR>\n" );
document.write( "A = amt after t time<BR>\n" );
document.write( "Ao = initial amt (t=0)<BR>\n" );
document.write( "t = time of decay<BR>\n" );
document.write( "h = half-life of the substance<BR>\n" );
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document.write( "A.) write a exponential function to model the decay of a 240-my sample.<BR>\n" );
document.write( "A = 240(2^(-t/5700)<BR>\n" );
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document.write( "B.) explain what each value in the function model represents.<BR>\n" );
document.write( "see above<BR>\n" );
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document.write( "C.) to the nearest hundredth, find the amount of carbon-14 remaining after 2353 years.<BR>\n" );
document.write( "A = 240(2^(-2353/5700)<BR>\n" );
document.write( "A = 240(2^(-.4128))<BR>\n" );
document.write( "using a calc<BR>\n" );
document.write( "A = 240*75116<BR>\n" );
document.write( "A = 180.3 grams remain after 2,353 yrs </SPAN>\n" );
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