document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=576785>Question 576785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> eight times the larger of two numbers decreased by three times the smaller is 148. nine times the smaller decreased by twenty is equal to eight times the larger. find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369993 by </B><A HREF=/tutors/aboutme.mpl?userid=chana><B>chana(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chana><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> eight times the larger of two numbers decreased by three times the smaller is 148. nine times the smaller decreased by twenty is equal to eight times the larger. find the two numbers<BR>\n" );
document.write( "sol :<BR>\n" );
document.write( "forming the equation with the given datas :<BR>\n" );
document.write( "let x be the larger number and y be the smaller number <BR>\n" );
document.write( "so as given 8x - 3y = 148 ------(1)<BR>\n" );
document.write( "9y - 20 = 8x ----------(2)<BR>\n" );
document.write( "solve the anove two equation for x & y ,you will get the required nos ,where x = 29 , y = 28. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );