document.write( "Question 576496: Find the equation of the line with slope -1 that is the tangent to the curve y=1/x-1\r
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document.write( "I'm pretty sure this involves rearranging this into a quadratic equation then using the discriminant (b^2-4ac) of the quadratic formula to find \"k\" in y=mx+k. \n" );
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Algebra.Com's Answer #369965 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Do you mean\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In either case, quadratics or discriminants won't help. Take dy/dx of both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "depending on whether you intend (1/x)-1 or 1/(x-1). Set dy/dx = -1, solve for x, find the equation of the tangent line using point-slope form (since you have the slope and you can find a point on the graph). \n" ); document.write( " |