document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=576665>Question 576665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company’s CEO wanted to estimate the percentage of defective product per shipment. In a sample containing 400 products, he found 25 defective products.\r<BR>\n" );
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document.write( "(a) Find a 95% confidence interval for the true proportion of defective product. Show your calculations and/or explain the process used to obtain the interval.<BR>\n" );
document.write( "(b) Interpret this confidence interval and write a sentence that explains it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369957 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A company’s CEO wanted to estimate the percentage of defective product per shipment. In a sample containing 400 products, he found 25 defective products.<BR>\n" );
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document.write( "(a) Find a 95% confidence interval for the true proportion of defective product. Show your calculations and/or explain the process used to obtain <BR>\n" );
document.write( "the interval.<BR>\n" );
document.write( "p-hat = 25/400 = 0.0625<BR>\n" );
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document.write( "ME = 1.96*sqrt[0.0625*0.9375/400] = 0.0237<BR>\n" );
document.write( "95%CI: 0.0625-0.0237 < p < 0.0625+0.0237<BR>\n" );
document.write( "95%CI: 0.0388 < p < 0.0862<BR>\n" );
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document.write( "(b) Interpret this confidence interval and write a sentence that explains it.<BR>\n" );
document.write( "With 95% confidence we can say that the proportion of defective products<BR>\n" );
document.write( "is between 3.88% and 8.62%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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