document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54765>Question 54765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a right circular cone leaking water (original dimensions of r=6m h=8m\r<BR>\n" );
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document.write( "1. Rewrite the formula for V in terms of the radius only.<BR>\n" );
document.write( "2. Rewrite the formula for V in terms of height only.<BR>\n" );
document.write( "3. If the volume is decreasing at a rate of 81/32 (pie) m^3/min. how fast is the height dropping when h=3m?\r<BR>\n" );
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document.write( "Please help...i've search so many places for help.  Lillian<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36995 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given a right circular cone leaking water (original dimensions of r=6m h=8m \r<BR>\n" );
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document.write( "1. Rewrite the formula for V in terms of the radius only.<BR>\n" );
document.write( "WHERE IS THE FORMULA?OK LET ME ASSUME<BR>\n" );
document.write( "V=PI*R^2*H/3..IF YOU WANT ONLY INTERMS OF RADIUS WE HAVE TO BE GIVEN SOME RELATION BETWEEN HEIGHT AND RADIUS..AGAIN LET ME ASSUME SLANT HEIGHT IS GIVEN AS 10.(THIS CORRESPONDS WITH H=8 FOR R=6,SINCE R^2+H^2=6^2+8^2=36+64=10^2=100).THEN <BR>\n" );
document.write( "R^2+H^2=10^2<BR>\n" );
document.write( "H= SQRT (100-R^2)<BR>\n" );
document.write( "HENCE <BR>\n" );
document.write( "V=PI*R^2/3\r<BR>\n" );
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document.write( "2. Rewrite the formula for V in terms of height only.<BR>\n" );
document.write( "SAME COMMENTS AS ABOVE APPLY..MAKING SAME ASSUMPTIONS<BR>\n" );
document.write( "R^2=100-H^2<BR>\n" );
document.write( "V=PI(100-H^2)*H/3\r<BR>\n" );
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document.write( "3. If the volume is decreasing at a rate of 81/32 (pie) m^3/min. how fast is the height dropping when h=3m?<BR>\n" );
document.write( "V=PI(100-H^2)H/3=(100H-H^3)PI/3<BR>\n" );
document.write( "DV/DT = (100-3H^2)(PI/3)DH/DT<BR>\n" );
document.write( "DV/DT = 81PI/32<BR>\n" );
document.write( "H=3<BR>\n" );
document.write( "DH/DT = {(81PI/32)}/{(100-3*3^2)PI/3}=(81*3)/(32*73)=243/2336=0.104\r<BR>\n" );
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document.write( "Please help...i've search so many places for help. Lillian\r<BR>\n" );
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