document.write( "Question 54769: A 25% SOLUTION OF ALCOHOL IS TO BE MIXED WITH A 40% SOLUTION TO GET 50L OF A FINAL MIXTURE THAT IS 30% alcohol. How much of each of the original solution should be used? \n" ); document.write( "
Algebra.Com's Answer #36993 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .25X+.40(50-X)=50*.30 \n" ); document.write( ".25X+20-.40X=15 \n" ); document.write( "-.15X=15-20 \n" ); document.write( "-.15X=-5 \n" ); document.write( "X=-5/-.15 [CORRECTION I USED .25 INSTEAD OF .15 - SORRY] \n" ); document.write( "X=33.33 L OF 25% ALCOHOL & \n" ); document.write( "50-33.33=16.67 L OF 40% ALCOHOL ARE USED TO CREATE A MIX OF 50 L WITH 30% ALCOHOL.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |