document.write( "Question 54769: A 25% SOLUTION OF ALCOHOL IS TO BE MIXED WITH A 40% SOLUTION TO GET 50L OF A FINAL MIXTURE THAT IS 30% alcohol. How much of each of the original solution should be used? \n" ); document.write( "
Algebra.Com's Answer #36993 by checkley71(8403)\"\" \"About 
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.25X+.40(50-X)=50*.30
\n" ); document.write( ".25X+20-.40X=15
\n" ); document.write( "-.15X=15-20
\n" ); document.write( "-.15X=-5
\n" ); document.write( "X=-5/-.15 [CORRECTION I USED .25 INSTEAD OF .15 - SORRY]
\n" ); document.write( "X=33.33 L OF 25% ALCOHOL &
\n" ); document.write( "50-33.33=16.67 L OF 40% ALCOHOL ARE USED TO CREATE A MIX OF 50 L WITH 30% ALCOHOL.\r
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