document.write( "Question 576543: 3(y+3y)=12 \n" ); document.write( "
Algebra.Com's Answer #369910 by jim_thompson5910(35256)\"\" \"About 
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\"3%28y%2B3y%29=12\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3y%2B9y=12\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"12y=12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2812%29%2F%2812%29\" Divide both sides by \"12\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"y=1\"
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