document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54735>Question 54735</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0471369039/algebrahomeworkh>technical mathematics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> i need to see how you work this problem with all steps shown:<BR>\n" );
document.write( "How many metric tons of chromium must be added to 2.50 metric tons of stainless steel to raise the percent chromium from 11% to 18%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36989 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2.5+X).18=2.5*.11+X<BR>\n" );
document.write( ".45+.18X=.275+X <BR>\n" );
document.write( ".45-.275=-.18+X <BR>\n" );
document.write( ".175=.82X <BR>\n" );
document.write( "X=.175/.82<BR>\n" );
document.write( "X=.2134 METRIC TONS OF CHROMIUM NEEDS TO BE ADDED TO 2.5 TONS OF 11% TO RAISE THE % OF CHROMIUM TO 18%<BR>\n" );
document.write( "PROOF <BR>\n" );
document.write( "(2.5+.2134).18=2.5*.11+.2134<BR>\n" );
document.write( "2.7134*.18=.275+.2134<BR>\n" );
document.write( ".488=.488 THE TOTAL AMOUNT OF CHROMIUM  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );