document.write( "Question 54711: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #36988 by tutorcecilia(2152)\"\" \"About 
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Ax+By=C [Use the standard equation of a line]
\n" ); document.write( "(14%)(x)+(12%)($20,000-x)=$2,720
\n" ); document.write( ".14x+.12(20,000-x)=2720
\n" ); document.write( ".14x+2400-.12x=2720 [Solve for x]
\n" ); document.write( ".14x-.12x=2720-2400
\n" ); document.write( ".02x=320
\n" ); document.write( "x=$16,000
\n" ); document.write( ".
\n" ); document.write( "14%of $16,000 = (.14)(16,000)=$2,240
\n" ); document.write( "12% of ($20,000-$16,000)=.12(20,000-16,000)=$480
\n" ); document.write( "So, $2,240+$480=$2,720
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