document.write( "Question 576499: 2. If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?\r
\n" ); document.write( "\n" ); document.write( "A. 2 hours and 24 minutes
\n" ); document.write( "B. 3 hours and 12 minutes
\n" ); document.write( "C. 3 hours and 44 minutes
\n" ); document.write( "D. 4 hours and 10 minutes
\n" ); document.write( "E. 4 hours and 33 minutes
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Algebra.Com's Answer #369872 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If A can do a job in x time periods, then A can do of the job in 1 time period. Likewise, if B can do the same job in y time periods, then B can do of the job in 1 time period.\r
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\n" ); document.write( "\n" ); document.write( "So, working together, they can do\r
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\n" ); document.write( "\n" ); document.write( "of the job in 1 time period.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, they can do the whole job in:\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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