document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=576480>Question 576480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the equation of the line which is perpendicular to y = -3x + 4 and goes through the point (6, -2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369859 by </B><A HREF=/tutors/aboutme.mpl?userid=kimberly_16><B>kimberly_16(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kimberly_16><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kimberly_16><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The solution to this problem is quite simple :\r<BR>\n" );
document.write( "\n" );
document.write( "First,to find the gradient of the line you divide -1 by -3 because the product of the gradient of perpendicular lines is -1.Therefore the gradient of the perpendicular line is 3.\r<BR>\n" );
document.write( "\n" );
document.write( "Now just substitute the points (6,-2) into the equation y =3x+ c\r<BR>\n" );
document.write( "\n" );
document.write( "You'll get -2 = 3(6)+c<BR>\n" );
document.write( "           -2 =18+c<BR>\n" );
document.write( "           -2-18=c<BR>\n" );
document.write( "            c=-20<BR>\n" );
document.write( "therefore eqn. of line perpendicular to y =-3x+4 is y =3x-20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );