document.write( "Question 576375: I tried this one for at least 45 minutes, and really need help, please.\r
\n" ); document.write( "\n" ); document.write( "Mr. Elliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the rest in a nuclear blast-proof bank. Mr. Elliot earned a 5% profit on his gold bullion and a 3% profit on the money in the bank. If he made a total of $5,500 from both investments, how much did he invest in gold bullion?\r
\n" ); document.write( "\n" ); document.write( "I tried both \r
\n" ); document.write( "\n" ); document.write( ".03x + .05(5,500 - x) = 150,000\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( ".03x + .05(150,000 - x) + 5,500\r
\n" ); document.write( "\n" ); document.write( "solving for both, but neither came out right.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance for your help!
\n" ); document.write( "

Algebra.Com's Answer #369828 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Mr. Elliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the rest in a nuclear blast-proof bank. Mr. Elliot earned a 5% profit on his gold bullion and a 3% profit on the money in the bank. If he made a total of $5,500 from both investments, how much did he invest in gold bullion?
\n" ); document.write( "I tried both
\n" ); document.write( "Equation:
\n" ); document.write( "Interest + interest = interest
\n" ); document.write( ".03x + .05(150,000 - x) = 5,500
\n" ); document.write( "----
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "3x + 5*150000 - 5x = 550000
\n" ); document.write( "----
\n" ); document.write( "-2x = 550000-750000
\n" ); document.write( "-2x = -200000
\n" ); document.write( "x = $100,000 (amt. invested at 3%
\n" ); document.write( "150,000-x = $50,000 (amt. invested at 5%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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