document.write( "Question 54763: A=PI*r2 if A=113.04sq ft and PI*=3.14 what is r \n" ); document.write( "

Algebra.Com's Answer #36979 by funmath(2933) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"A=pi%2Ar%5E2\"$ if A=113.04sq ft and $\"pi\"$ =3.14 what is r
\n" ); document.write( "Solve the formula for r and plug in your numbers.
\n" ); document.write( " $\"A%2F%28pi%29=%28pi%29%2Ar%5E2%2F%28pi%29\"$
\n" ); document.write( " $\"A%2F%28pi%29=cross%28%28pi%29%29%2Ar%5E2%2Fcross%28%28pi%29%29\"$
\n" ); document.write( " $\"A%2F%28pi%29=r%5E2\"$
\n" ); document.write( " $\"sqrt%28A%2F%28pi%29%29=sqrt%28r%5E2%29\"$ (you don't need to use + or - because you can't have a negative radius.)
\n" ); document.write( " $\"r=sqrt%28A%2F%28pi%29%29\"$ A=113.04 ft^2 and $\"%28pi%29\"$ =3.14
\n" ); document.write( " $\"r=sqrt%28113.04ft%5E2%2F%283.14%29%29\"$
\n" ); document.write( " $\"r=sqrt%2836ft%5E2%29\"$
\n" ); document.write( " $\"r=sqrt%28%286ft%29%286ft%29%29\"$
\n" ); document.write( " $\"highlight%28r=6+ft%29\"$
\n" ); document.write( "Happy Calculating!!!
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