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You can put this solution on YOUR website!
Help!!!!!!!!!!!!! My boyfriend (majoring in engineering) says if I can get this solved for P (Proposal) that is a hint as to the number of weeks until he proposes! I think I know the answer but can you help me?
\n" ); document.write( "p2 + 3p + 2
\n" ); document.write( "____________ = 3/2 + 3p -3
\n" ); document.write( "p + 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "OK THIS IS MY BIT TO YOUR HAPPINESS WITH YOUR BOY FRIEND THOUGH IT LOOKS A STRANGE TEST!!\r
\n" ); document.write( "\n" ); document.write( "p2 + 3p + 2
\n" ); document.write( "____________ = 3/2 + 3p -3 = 1.5+3P-3....MULTIPLYING BOTH SIDES WITH P+1,WE GET
\n" ); document.write( "p + 1
\n" ); document.write( "(THIS TAKES IN TO ACCOUNT THAT P+1=0...OR...P=-1 .IS NOT POSSIBLE.THAT IS HE WOULD HAVE ALREADY PROPOSED TO YOU A WEEK AGO!!!HE HAS NOT DONE SO AS PER YOU!!..SO..IT IS OK)
\n" ); document.write( "P^2+3P+2=(P+1)(1.5+3P-3)=1.5P+3P^2-3P+1.5+3P-3=1.5P+3P^2-1.5
\n" ); document.write( "1.5P+3P^2-1.5-P^2-3P-2=0
\n" ); document.write( "2P^2-1.5P-3.5=0............MULTIPLYING WITH 2 TO REMOVE FRACTIONS..
\n" ); document.write( "4P^2-3P-7=0
\n" ); document.write( "4P^2-7P+4P-7=0
\n" ); document.write( "P(4P-7)+1(4P-7)=0
\n" ); document.write( "(4P-7)(P+1)=0....BUT P+1 IS NOT ZERO AS WE ALREADY CONCLUDED ABOVE!
\n" ); document.write( "4P-7=0
\n" ); document.write( "4P=7
\n" ); document.write( "P=7/4=1.75 WEEKS ! OH GOSH! IT IS ONLY (OR TOO FAR FOR YOU?) ANOTHER 12 DAYS AWAY!!THAT IS OVER NEXT WEEK END!!DONT FORGET TO GIVE ME A TREAT THEN!!!!!!!!!!!!!!I AM WAITING!! \n" ); document.write( "