document.write( "Question 576139: Write an equation in standard form for the line perpendicular to 8x+y=5 that passes through the point (3, 4) \n" ); document.write( "

Algebra.Com's Answer #369740 by mananth(16946) $\"\"$ $\"About$

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8 x + 1 y = 5
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "1 y = -8 x + 5
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -8 x + 5
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -8
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 1/8
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 1/8
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\n" ); document.write( "m= 1/8 ,point ( 3 , 4 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "4 = 3/ 8 + b
\n" ); document.write( "b= 29/8
\n" ); document.write( "m= 1/8
\n" ); document.write( "The required equation is y = 1/ 8 x +29/ 8
\n" ); document.write( "m.ananth@hotmail.ca
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