document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=576073>Question 576073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3a+3-6a > 15  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369712 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369712\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3a+3-6a > 15 \r<BR>\n" );
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document.write( "-3a+3 > 15 \r<BR>\n" );
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document.write( "-3a > 15 - 3\r<BR>\n" );
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document.write( "-3a > 12\r<BR>\n" );
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document.write( "a < 12/(-3) ... Keep in mind that the sign flips when dividing both sides by a negative number\r<BR>\n" );
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document.write( "a < -4\r<BR>\n" );
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document.write( "So the solution is   a < -4 </SPAN>\n" );
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