document.write( "Question 575980: Three siblings have a combines age of 108 yrs. The oldest is 8 years older than the youngest. what are the ages of the siblings? \n" ); document.write( "
Algebra.Com's Answer #369709 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Three unknowns, two equations, calls for some reasoning here. \r \n" ); document.write( "\n" ); document.write( "Three siblings have a combined age of 108 yrs. \n" ); document.write( "a + b + c = 108 \n" ); document.write( "; \n" ); document.write( "The oldest is 8 years older than the youngest. \n" ); document.write( "a = c + 8 \n" ); document.write( ": \n" ); document.write( "a + b + c = 108 \n" ); document.write( "(c+8) + b + c = 108 \n" ); document.write( "2c + b = 108 - 8 \n" ); document.write( "2c = b = 100 \n" ); document.write( "b = -2c + 100 \n" ); document.write( "we know b is < 8 and > 1 yr more than c \n" ); document.write( "c = 31 \n" ); document.write( "b = -2(31) + 100 \n" ); document.write( "b = 38 \n" ); document.write( "or \n" ); document.write( "c = 32 \n" ); document.write( "b = -2(32) + 100 \n" ); document.write( "b = 36 \n" ); document.write( "and \n" ); document.write( "c = 33 \n" ); document.write( "b = -2(33) + 100 \n" ); document.write( "b = 34 \n" ); document.write( ": \n" ); document.write( "So we have three possibilities: \n" ); document.write( "a = 39 \n" ); document.write( "b = 38 \n" ); document.write( "c = 31 \n" ); document.write( "or \n" ); document.write( "a = 40 \n" ); document.write( "b = 36 \n" ); document.write( "c = 32 \n" ); document.write( "or \n" ); document.write( "a = 41 \n" ); document.write( "b = 34 \n" ); document.write( "c = 33 \n" ); document.write( " |