document.write( "Question 575999: x^2+y^2+6x+4y+12=0 \n" ); document.write( "
Algebra.Com's Answer #369679 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x^2+y^2+6x+4y+12=0 \n" ); document.write( "---- \n" ); document.write( "Complete the square on the x-terms and on the y-terms. \n" ); document.write( "---- \n" ); document.write( "x^2+6x+9 + y^2+4y+4 + 12 -13 = 0 \n" ); document.write( "(x+3)^2 + (y+2)^2 = 1 \n" ); document.write( "--- \n" ); document.write( "Circle with center at (-3,-2); radius = 1 \n" ); document.write( "============================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |