document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=575862>Question 575862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of twice a number and 4 is -12.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369657 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"the sum of twice a number and 4 is -12\" translates to 2n+4 = -12, solve for n to get\r<BR>\n" );
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document.write( "2n + 4 = -12\r<BR>\n" );
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document.write( "2n = -12 - 4\r<BR>\n" );
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document.write( "2n = -16\r<BR>\n" );
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document.write( "n = -16/2\r<BR>\n" );
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document.write( "n = -8\r<BR>\n" );
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document.write( "So the unknown number is -8 </SPAN>\n" );
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