document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=575920>Question 575920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a large company, there are 3 vice presidents, 15 managers and 1 CEO. If a person is selected at random, find the probability that the person is either the CEO or a manager. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369654 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(CEO or manager) = P(CEO) + P(Manager)\r<BR>\n" );
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document.write( "P(CEO or manager) = 1/(3+15+1) + 15/(3+15+1)\r<BR>\n" );
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document.write( "P(CEO or manager) = 1/19 + 15/19\r<BR>\n" );
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document.write( "P(CEO or manager) = 16/19 </SPAN>\n" );
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