document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=575893>Question 575893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The function is:  f(x)= x(2-x)(x+3)^2\r<BR>\n" );
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document.write( "Give each zero and it's mulplicity. There are three. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369638 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)= x(2-x)(x+3)^2\r<BR>\n" );
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document.write( "0= x(2-x)(x+3)^2\r<BR>\n" );
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document.write( "x(2-x)(x+3)^2 = 0\r<BR>\n" );
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document.write( "x=0 or 2-x = 0 or (x+3)^2 = 0\r<BR>\n" );
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document.write( "x=0 or x = 2 or x = -3\r<BR>\n" );
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document.write( "The first two zeros are of multiplicity 1 and the last zero is of multiplicity 2. </SPAN>\n" );
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