document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=575698>Question 575698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right angled triangle two of the angles are in the ratio 6:13.find the third angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369590 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle a b c<BR>\n" );
document.write( "one angle =90 degrees<BR>\n" );
document.write( "the other two added together =90 degrees<BR>\n" );
document.write( "all 3 angles added together =180 degrees<BR>\n" );
document.write( "no single angle can be more than 90 degrees<BR>\n" );
document.write( "angle a to angle b is 6:13 or 6x:13x<BR>\n" );
document.write( "a=6x<BR>\n" );
document.write( "b=13x<BR>\n" );
document.write( "c is unknown (third angle)<BR>\n" );
document.write( "****<BR>\n" );
document.write( "by using the above facts<BR>\n" );
document.write( ".<BR>\n" );
document.write( "a cant possibly be the 90 degree angle beacause then b would be greater than 90 degrees<BR>\n" );
document.write( "just to prove it<BR>\n" );
document.write( "if a=90 then 6x=90 and x=15<BR>\n" );
document.write( "and then b=13x=13(15)=195 and thats biggere then the entire triangle<BR>\n" );
document.write( "****<BR>\n" );
document.write( "so if b=90 degrees<BR>\n" );
document.write( "13x=90<BR>\n" );
document.write( "x=6.92<BR>\n" );
document.write( ".<BR>\n" );
document.write( "a=6(6.92)=41.5385<BR>\n" );
document.write( ".<BR>\n" );
document.write( "c=180-90-41.5385=48.4615<BR>\n" );
document.write( "****<BR>\n" );
document.write( "but if c=90 degrees then that would mean <BR>\n" );
document.write( "6x+13x=90<BR>\n" );
document.write( "19x=90<BR>\n" );
document.write( "x=4.7368<BR>\n" );
document.write( "a=6x=6(4.7368)=28.4211<BR>\n" );
document.write( "b=13x=13(4.7368)=61.5789<BR>\n" );
document.write( "****<BR>\n" );
document.write( "so there are 2 possible answers either c=48.4615 or 90 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );