document.write( "Question 575691: . An electrical firm manufactures light bulbs that have a length of life that is normally distributed with mean equal to 800 hours and standard deviation of 40 hours. Find the probability that a bulb burns between 778 and 834 hours. \n" ); document.write( "
Algebra.Com's Answer #369585 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
An electrical firm manufactures light bulbs that have a length of life that is normally distributed with mean equal to 800 hours and standard deviation of 40 hours. Find the probability that a bulb burns between 778 and 834.
\n" ); document.write( "---------------
\n" ); document.write( "Using z-calculations:
\n" ); document.write( "z(778) = (778-800)/40 = -0.55
\n" ); document.write( "z(834) = (834-800)/40 = 0.85
\n" ); document.write( "P(778<= x <=834) = P(-0.55<= z <=0.85) = normalcdf(-0.55,0.85) = 0.5112
\n" ); document.write( "==================================================\r
\n" ); document.write( "\n" ); document.write( "Using a TI-84:
\n" ); document.write( "normalcdf(778,834,800,40) = 0.5112
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============
\n" ); document.write( "
\n" );