document.write( "Question 575599: how can $54000 be invested, part at 12%annual simple interest and the remainder at 6%.so that the interest earned by the two accounts will be eqaul \n" ); document.write( "
Algebra.Com's Answer #369546 by mananth(16946) You can put this solution on YOUR website! let investment @ 12% be x \n" ); document.write( "and 6 % be y\r \n" ); document.write( "\n" ); document.write( "x+y = 54000...................1\r \n" ); document.write( "\n" ); document.write( "12%x=6*%y\r \n" ); document.write( "\n" ); document.write( "multiply by 100\r \n" ); document.write( "\n" ); document.write( "12x=6y \n" ); document.write( "x= y/2\r \n" ); document.write( "\n" ); document.write( "substitute x in (1) \n" ); document.write( "y/2 + y =54000\r \n" ); document.write( "\n" ); document.write( "multiply by 2 \n" ); document.write( "y+2y= 108000 \n" ); document.write( "3y=108000 \n" ); document.write( "/3 \n" ); document.write( "y=36000\r \n" ); document.write( "\n" ); document.write( "$36,000 @ 6% \n" ); document.write( "$18000 @ 12 % \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |