document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54747>Question 54747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am stuck on correct answer for:\r<BR>\n" );
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document.write( "2 to the power of negative 3 =\r<BR>\n" );
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document.write( "I think it equals -8. What is correct answer?\r<BR>\n" );
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document.write( "I am not using any specific book. I am just practicing.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36953 by </B><A HREF=/tutors/aboutme.mpl?userid=anjulasahay><B>anjulasahay(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anjulasahay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 to the power of negative 3 = 2^(-3) = 1/2^3=1/8<BR>\n" );
document.write( "hence ans: 1/8. </SPAN>\n" );
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