document.write( "Question 575507: 1) write the equation in slope intercept form (solved for y), when possible. Through (6,-7) parallel to the y-axis\r
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\n" ); document.write( "\n" ); document.write( "2) write the equation in slope intercept form (solved for y), when possible. Through (-1,-6) perpendicular to the y-axis\r
\n" ); document.write( "\n" ); document.write( "3) Find an equation of the line with the given slope that passes through a given point. write the equation Ax+By=C .... m= -1, (-5,-9)
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Algebra.Com's Answer #369499 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "I already answered this one.\r
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\n" ); document.write( "\n" ); document.write( "A line parallel to the -axis is a vertical line. Vertical lines have a couple of interesting characteristics. In the first place, ALL of the -coordinates of the set of ordered pairs that comprise the line have to be identical. Since all of the -coordinates are equal, no matter which two points you choose for the purposes of computing the slope, the slope fraction will have a zero denominator. Hence, the slope of any vertical line is undefined.\r
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\n" ); document.write( "\n" ); document.write( "You can't write the equation of a vertical line in slope-intercept form because the slope quantity is undefined. However, since the -coordinates of all the points on the line are identical, the equation of a vertical line passing through the point is uniquely defined by the equation \r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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