document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54697>Question 54697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of Earth is about twice that of Mars.  The diameter of Mars is about three times that of Pluto.  Together, the sum of the diameters of Earth, Mars, and Pluto is about 30,000 kilometers less than the diameter of Uranus.  If the diameter of Uranus is about 52,000 kilometers, what equation would be used to find the approximate diameter of Pluto?  Let d = diameter of Pluto. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36943 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of Earth is about twice that of Mars.<BR>\n" );
document.write( "           E = 2M<BR>\n" );
document.write( ":<BR>\n" );
document.write( " The diameter of Mars is about three times that of Pluto.<BR>\n" );
document.write( "           M = 3d  &  E = 2M<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "           E = 2(3d)<BR>\n" );
document.write( "           E = 6d<BR>\n" );
document.write( ":<BR>\n" );
document.write( " Together, the sum of the diameters of Earth, Mars, and Pluto is about 30,000 kilometers less than the diameter of Uranus.<BR>\n" );
document.write( "                 E + M + d = U - 30000<BR>\n" );
document.write( ":<BR>\n" );
document.write( " If the diameter of Uranus is about 52,000 kilometers, what equation would be used to find the approximate diameter of Pluto? Let d = diameter of Pluto.\r<BR>\n" );
document.write( "\n" );
document.write( "              d = U - 30000 - E - M<BR>\n" );
document.write( "              d = 52000 - 30000 - E -M<BR>\n" );
document.write( "              d = 22000 - E - M<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Substitute 6d for E and 3d for M<BR>\n" );
document.write( "              d = 22000 - 6d - 3d<BR>\n" );
document.write( "              d = 22000 - 9d<BR>\n" );
document.write( "         d + 9d = 22000<BR>\n" );
document.write( "            10d = 22000<BR>\n" );
document.write( "              d = 22000/10<BR>\n" );
document.write( "              d = 2200 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );