document.write( "Question 575063: I rowed 20 km up a river that had a steady current in 5 hours and returned downstream in 2.5 hours. How fast would I have rowed the boat in still water, and what is the speed of the current?\r
\n" ); document.write( "\n" ); document.write( "Let x be the speed of the boat in still water and y the speed of the current (km/h). The speed of the boat going upstream is (x –y) km/h and the speed of the boat going downstream is (x+y) km/h,.
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Algebra.Com's Answer #369365 by stanbon(75887)\"\" \"About 
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I rowed 20 km up a river that had a steady current in 5 hours and returned downstream in 2.5 hours. How fast would I have rowed the boat in still water, and what is the speed of the current?
\n" ); document.write( "Let x be the speed of the boat in still water and y the speed of the current (km/h). The speed of the boat going upstream is (x –y) km/h and the speed of the boat going downstream is (x+y) km/h,.
\n" ); document.write( "---
\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 20 km ; rate = (x-y)km/h ; time = 20/(x-y) hr
\n" ); document.write( "------------------
\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 20 km ; rate = (x+y)km/h ; time = 20/(x+y) hr
\n" ); document.write( "----
\n" ); document.write( "Equation:
\n" ); document.write( "20/(x-y) = 5 hrs
\n" ); document.write( "20/(x+y) = 2.5 hrs
\n" ); document.write( "---------------------------
\n" ); document.write( "x-y = 4
\n" ); document.write( "x+y = 8
\n" ); document.write( "____
\n" ); document.write( "Add and solve for \"x\":
\n" ); document.write( "2x = 12
\n" ); document.write( "x = 6 km/h (boat speed in calm water)
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\n" ); document.write( "Solve for \"y\":
\n" ); document.write( "x+y = 8
\n" ); document.write( "y = 2 km/h (current speed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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