document.write( "Question 574971: How do you factor x^3-7x^2-9x+63 \n" ); document.write( "

Algebra.Com's Answer #369338 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"x%5E3-7x%5E2-9x%2B63\"$ Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%5E3-7x%5E2%29%2B%28-9x%2B63%29\"$ Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2%28x-7%29-9%28x-7%29\"$ Factor out the GCF $\"x%5E2\"$ out of the first group. Factor out the GCF $\"-9\"$ out of the second group\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2-9%29%28x-7%29\"$ Since we have the common term $\"x-7\"$ , we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x-3%29%28x%2B3%29%28x-7%29\"$ Now factor $\"x%5E2-9\"$ to get $\"%28x-3%29%28x%2B3%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "So $\"x%5E3-7x%5E2-9x%2B63\"$ factors to $\"%28x-3%29%28x%2B3%29%28x-7%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"x%5E3-7x%5E2-9x%2B63=%28x-3%29%28x%2B3%29%28x-7%29\"$
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