document.write( "Question 574749: (x-7)/(square root x-1) + 3(x-1)^1/2=0\r
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Algebra.Com's Answer #369278 by ad_alta(240) $\"\"$ $\"About$

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If you mean to solve (x-7)/(x-1)^{1/2} + 3(x-1)^{1/2}=0, the easiest way to proceed is to multiply both sides by (x-1)^{1/2}. That gives 4x-10=0, so x=5/2. If you mean (x-7)/(x^{1/2}-1) + 3(x-1)^{1/2}=0 the best way is to multiply by the square root conjugate (x^{1/2}+1), although the equation is still quite nasty. I think you probably meant the former. \n" ); document.write( "

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