document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=573848>Question 573848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the information provided to write the vertex form equation of each parabola.<BR>\n" );
document.write( "vertex(-6,9) focus (-6,109/12) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369261 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the information provided to write the vertex form equation of each parabola.<BR>\n" );
document.write( "vertex(-6,9) focus (-6,109/12)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Standard form of equation for parabola opening upwards: <BR>\n" );
document.write( "(x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the center.<BR>\n" );
document.write( "For given parabola:<BR>\n" );
document.write( "vertex: (-6,9) (given)<BR>\n" );
document.write( "axis of symmetry:x=-6<BR>\n" );
document.write( "p=(109/12)-9=(109/12)-(108/12)=1/12 (distance from vertex to focus on the axis of symmetry)<BR>\n" );
document.write( "4p=4/12=1/3<BR>\n" );
document.write( "equation:<BR>\n" );
document.write( "(x+6)^2=(1/3)(y-9)  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );