document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=574616>Question 574616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you get the equation y=-2(x+8)^2+9 in standard form of a parabola?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #369198 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=369198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you get the equation y=-2(x+8)^2+9 in standard form <BR>\n" );
document.write( "FOIL (x+8)(x+8)<BR>\n" );
document.write( "y = -2(x^2 + 8x + 8x + 64) + 9<BR>\n" );
document.write( "y = -2(x^2 + 16x + 64) + 9<BR>\n" );
document.write( "y = -2x^2 - 32x - 128 + 9<BR>\n" );
document.write( "y = -2x^2 - 32x - 119 </SPAN>\n" );
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