document.write( "Question 574570: An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #369176 by ankor@dixie-net.com(22740)\"\" \"About 
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An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away.
\n" ); document.write( "The express travels twice as fast as the local and arrives 1 hour ahead of the local.
\n" ); document.write( " Find the speed of each train.
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\n" ); document.write( "let s = speed of the local
\n" ); document.write( "then
\n" ); document.write( "2s = speed of the express
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\n" ); document.write( "write a time equation: time = dist/speed
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\n" ); document.write( "Local time - Express time = 1 hr
\n" ); document.write( "\"50%2Fs\" - \"50%2F%282s%29\" = 1
\n" ); document.write( "Multiply by 2s
\n" ); document.write( "2s*\"50%2Fs\" - 2s*\"50%2F%282s%29\" = 2s(1)
\n" ); document.write( "cancel the denominators
\n" ); document.write( "2(50) - 50 = 2s
\n" ); document.write( "100 - 50 = 2s
\n" ); document.write( "50 = 2s; 50 mph is the speed of express
\n" ); document.write( "and
\n" ); document.write( "s = 50/2 = 25 mph is the speed of the local
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\n" ); document.write( ":
\n" ); document.write( "Check this by finding the time of each
\n" ); document.write( "Local: 50/25 = 2 hrs
\n" ); document.write( "Expre: 50/50 = 1 hr
\n" ); document.write( "--------------------
\n" ); document.write( "difference = 1 hr
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