document.write( "Question 54689: 1.12x + 1.08y = 0
\n" ); document.write( "x+y = 500\r
\n" ); document.write( "\n" ); document.write( "No clue where to start. Please help.
\n" ); document.write( "

Algebra.Com's Answer #36915 by checkley71(8403)\"\" \"About 
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X+Y=500 OR X=500-Y NOW SUBSTITUTE (500-Y) FOR X IN EQUATION #1
\n" ); document.write( "WE GET 1.12(500-Y)+1.08Y=0
\n" ); document.write( "560-1.12Y+1.08Y=0
\n" ); document.write( "-.04Y=-560
\n" ); document.write( "Y=-560/-.04
\n" ); document.write( "Y=14,000 THEN
\n" ); document.write( "X+14,000=500
\n" ); document.write( "X=500-14,000
\n" ); document.write( "X=-13,500
\n" ); document.write( "PROOF
\n" ); document.write( "1.12(-13,500)+1.08*14,000=0
\n" ); document.write( "-15,120+15,120=0
\n" ); document.write( "0=0
\n" ); document.write( "
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