document.write( "Question 54689: 1.12x + 1.08y = 0
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document.write( "x+y = 500\r
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document.write( "No clue where to start. Please help. \n" );
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Algebra.Com's Answer #36915 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=500 OR X=500-Y NOW SUBSTITUTE (500-Y) FOR X IN EQUATION #1 \n" ); document.write( "WE GET 1.12(500-Y)+1.08Y=0 \n" ); document.write( "560-1.12Y+1.08Y=0 \n" ); document.write( "-.04Y=-560 \n" ); document.write( "Y=-560/-.04 \n" ); document.write( "Y=14,000 THEN \n" ); document.write( "X+14,000=500 \n" ); document.write( "X=500-14,000 \n" ); document.write( "X=-13,500 \n" ); document.write( "PROOF \n" ); document.write( "1.12(-13,500)+1.08*14,000=0 \n" ); document.write( "-15,120+15,120=0 \n" ); document.write( "0=0 \n" ); document.write( " |