document.write( "Question 574509: 3(x+1)^(4/3) = 48 \n" ); document.write( "

Algebra.Com's Answer #369135 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's first simplify it a bit. I cannot get those exponents to show properly, but you know what I mean.
\n" ); document.write( " $\"3%28x%2B1%29%5E%284%2F3%29=+48\"$ --> $\"3%28x%2B1%29%5E%284%2F3%29%2F3+=+48%2F3\"$ --> $\"%28x%2B1%29%5E%284%2F3%29+=+16\"$
\n" ); document.write( "The rest gets a little more creative, using properties of exponents. (Note that I got creative writing $\"%283%2F4%29\"$ as 0.75 at one point. I did it to avoid the problem with the tops of exponents being chopped off).
\n" ); document.write( " $\"%28x%2B1%29%5E%284%2F3%29+=+16\"$ --> $\"%28%28x%2B1%29%5E%284%2F3%29%29%5E%283%2F4%29+=+16%5E%283%2F4%29\"$ --> $\"%28x%2B1%29%5E%28%284%2F3%29%2A%283%2F4%29%29=%282%5E4%29%5E%283%2F4%29\"$ --> $\"%28x%2B1%29%5E1=2%5E%28%284%2A0.75%29%29\"$ --> $\"x%2B1=2%5E3\"$ --> $\"x%2B1=8\"$ --> $\"highlight%28x=7%29\"$ \n" ); document.write( "

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