document.write( "Question 574463: A rectangular lot uses 260 feet of fencing and uses a wall as one side. An expensive fencing along the lot's length costs $2o per foot and an inexpensive fencing along the two side widths cost only $8 per foot. The total cost of the fencing along the three sides comes to $3280. What are the lot's dimention (length and width).? \n" ); document.write( "
Algebra.Com's Answer #369124 by ankor@dixie-net.com(22740)\"\" \"About 
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rectangular lot uses 260 feet of fencing and uses a wall as one side.
\n" ); document.write( " An expensive fencing along the lot's length costs $2o per foot and
\n" ); document.write( " an inexpensive fencing along the two side widths cost only $8 per foot.
\n" ); document.write( " The total cost of the fencing along the three sides comes to $3280.
\n" ); document.write( " What are the lot's dimensions (length and width)?
\n" ); document.write( ":
\n" ); document.write( "Only 3 sides, therefore:
\n" ); document.write( "L + 2W = 260
\n" ); document.write( "L = (260-2W)\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "Total cost
\n" ); document.write( "20L + 8(2W) = 3280
\n" ); document.write( "20L + 16W = 3280
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "5L + 4W = 820
\n" ); document.write( "Replace L with (260-2W)
\n" ); document.write( "5(260-2W) + 4W = 820
\n" ); document.write( "1300 - 10W + 4W = 820
\n" ); document.write( "-6W = 820 - 1300
\n" ); document.write( "-6W = -480
\n" ); document.write( "W = \"%28-480%29%2F%28-6%29\"
\n" ); document.write( "W = +80 ft is the width
\n" ); document.write( "then
\n" ); document.write( "L = 260 - 2(80)
\n" ); document.write( "L = 100 ft is the length
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the cost:
\n" ); document.write( "20(100) = 2000
\n" ); document.write( "8(2*80) = 1280
\n" ); document.write( "---------------
\n" ); document.write( "totals: 3280
\n" ); document.write( "
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