document.write( "Question 574463: A rectangular lot uses 260 feet of fencing and uses a wall as one side. An expensive fencing along the lot's length costs $2o per foot and an inexpensive fencing along the two side widths cost only $8 per foot. The total cost of the fencing along the three sides comes to $3280. What are the lot's dimention (length and width).? \n" ); document.write( "
Algebra.Com's Answer #369124 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! rectangular lot uses 260 feet of fencing and uses a wall as one side. \n" ); document.write( " An expensive fencing along the lot's length costs $2o per foot and \n" ); document.write( " an inexpensive fencing along the two side widths cost only $8 per foot. \n" ); document.write( " The total cost of the fencing along the three sides comes to $3280. \n" ); document.write( " What are the lot's dimensions (length and width)? \n" ); document.write( ": \n" ); document.write( "Only 3 sides, therefore: \n" ); document.write( "L + 2W = 260 \n" ); document.write( "L = (260-2W)\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "Total cost \n" ); document.write( "20L + 8(2W) = 3280 \n" ); document.write( "20L + 16W = 3280 \n" ); document.write( "Simplify, divide by 4 \n" ); document.write( "5L + 4W = 820 \n" ); document.write( "Replace L with (260-2W) \n" ); document.write( "5(260-2W) + 4W = 820 \n" ); document.write( "1300 - 10W + 4W = 820 \n" ); document.write( "-6W = 820 - 1300 \n" ); document.write( "-6W = -480 \n" ); document.write( "W = \n" ); document.write( "W = +80 ft is the width \n" ); document.write( "then \n" ); document.write( "L = 260 - 2(80) \n" ); document.write( "L = 100 ft is the length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the cost: \n" ); document.write( "20(100) = 2000 \n" ); document.write( "8(2*80) = 1280 \n" ); document.write( "--------------- \n" ); document.write( "totals: 3280 \n" ); document.write( " |