document.write( "Question 574456: todd cardella invested 10,000, from which he earns annual interest income of $550 per year. he invested part of the 10,000 at 5% annual interest and the remainder bonds paying 6% interest. how much did he invest at each year? \n" ); document.write( "
Algebra.Com's Answer #369101 by reviewermath(1029)\"\" \"About 
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Let x=amount invested at 5% annual interest
\n" ); document.write( "so 10000-x = amount invested at 6% annual interest\r
\n" ); document.write( "\n" ); document.write( "0.05x + 0.06(10000-x) = 550
\n" ); document.write( "0.05x + 600 - 0.06x = 550
\n" ); document.write( "-0.01x = -50
\n" ); document.write( "x = 5000
\n" ); document.write( "10000-x = 5000
\n" ); document.write( "Answer: $5000 invested at 5% interest and the remaining $5000 invested at 6% interest.
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