document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54681>Question 54681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A principal of $2500 is invested; part at 8% per annum and the rest at 12% per annum. In one year, the two investments earned equal amounts of interest. How much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36908 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .12*x=.08(2500-x) or .12x=200-.08x or .2x=200 or x=200/.2 or x=1000 thus\r<BR>\n" );
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document.write( "$1,000*.12=$120 & .08*(2500-1000) or .08*1500=120 thus the interest for both investments are $120. </SPAN>\n" );
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