document.write( "Question 54672This question is from textbook Beginning Algebra
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\n" ); document.write( "\n" ); document.write( "-3s^2-10s+8\r
\n" ); document.write( "\n" ); document.write( "I can't get my signs to be correct in order for the 10 to be negative. What am I doing wrong? \n" ); document.write( "
Algebra.Com's Answer #36905 by Edwin McCravy(20086)\"\" \"About 
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-3s2-10s+8 \r\n" );
document.write( "I can't get my signs to be correct in order for the \r\n" );
document.write( "10 to be negative. What am I doing wrong?\r\n" );
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document.write( "-3s2 - 10z + 8\r\n" );
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document.write( "Whenever the first term is negative, always begin by\r\n" );
document.write( "factoring out -1, which will change all the signs\r\n" );
document.write( "inside the parentheses.\r\n" );
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document.write( "-1(3s2 + 10s - 8)\r\n" );
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document.write( "1. Multiply 3 by 8, getting 24\r\n" );
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document.write( "2. Think of two positive integers whose product is 24\r\n" );
document.write( "and whose difference (since the last sign is negative)\r\n" );
document.write( "is 10.  These are 12 and 2.\r\n" );
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document.write( "3. Attach signs to 12s and 2s so they will combine to\r\n" );
document.write( "give the middle term +10s.  So we attach + to the 12s \r\n" );
document.write( "and - to the 2s\r\n" );
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document.write( "4. Rewrite the middle term +10s as +12s - 2s.  Change \r\n" );
document.write( "the parentheses to brackets, since they will soon\r\n" );
document.write( "contain parentheses themselves.\r\n" );
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document.write( "-1[3s2 + 12s - 2s - 8]\r\n" );
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document.write( "5. Factor the first two terms in the brackets by taking \r\n" );
document.write( "out 3s.  Factor the last two terms in the brackets by \r\n" );
document.write( "taking out -2\r\n" );
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document.write( "-1[3s(s + 4) - 2(s + 4]]\r\n" );
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document.write( "6. Factor (s + 4) out of the two terms in the brackets:\r\n" );
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document.write( "-1[(s + 4)(3s - 2)]\r\n" );
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document.write( "7. Erase the brackets\r\n" );
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document.write( "-1(s + 4)(3s - 2)\r\n" );
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document.write( "8. Dispense with the 1 but leave the negative sign:\r\n" );
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document.write( "-(s + 4)(3s - 2) \r\n" );
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document.write( "Edwin
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