document.write( "Question 574208: If you have a mixture of 1 oz. of 35% hydrogen peroxide, how much pure water would you add to make a mixture of 17% hydrogen peroxide? \n" ); document.write( "
Algebra.Com's Answer #369044 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! you have a mixture of 1 oz. of 35% hydrogen peroxide, how much pure water would you add to make a mixture of 17% hydrogen peroxide? \n" ); document.write( ": \n" ); document.write( "let x = amt of water to produce a 17% mixture \n" ); document.write( ": \n" ); document.write( "amt of hydrogen peroxide remains the same; only the mixture amt changes \n" ); document.write( ": \n" ); document.write( ".35(1) = .17(x+1) \n" ); document.write( ".35 = .17x + .17 \n" ); document.write( ".35 - .17 = .17x \n" ); document.write( ".18 = .17x \n" ); document.write( "x = .18/.17 \n" ); document.write( "x = 1.06 oz of water to be added \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |