document.write( "Question 573964: Express y as a function of x (The constant c is a positive number):
\n" ); document.write( "ln(y+4) = 5x + ln(c)
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Algebra.Com's Answer #369037 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
To express y as a function of x we just have to \"solve for y\". To do this we need to get the y out of the logarithm. To do that we need to rewrite the equation in exponential form.

\n" ); document.write( "In general
\n" ); document.write( "\"log%28a%2C+%28p%29%29+=+q\" is equivalent to:
\n" ); document.write( "\"a%5Eq+=+p\"
\n" ); document.write( "Using
  • this pattern with the \"p\" being \"y+4\" and the \"q\" being \"5x+ln(c)\"
  • the fact that the base of ln is e, making the \"a\" an \"e\"
we get (hold on!):
\n" ); document.write( "\"e%5E%285x+%2B+ln%28c%29%29+=+y+%2B+4\"
\n" ); document.write( "Now we just need to subtract 4 from each side:
\n" ); document.write( "\"e%5E%285x+%2B+ln%28c%29%29+-+4+=+y\"
\n" ); document.write( "We now have y as a function of x!
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