document.write( "Question 574263: Two cars are 261 miles apart, they travel towards each other and meet in 3 Hrs. 1 car travels 1 MPH faster than the other. What is average speed of each car?\r
\n" ); document.write( "\n" ); document.write( "I believe I have this set up correctly but instructor marked it incorrect.\r
\n" ); document.write( "\n" ); document.write( "D/t=r
\n" ); document.write( "261/3=r
\n" ); document.write( "87=r of one car
\n" ); document.write( "R+1=88mph of second car
\n" ); document.write( "Is there anything I am leaving our?
\n" ); document.write( "

Algebra.Com's Answer #369005 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Two cars are 261 miles apart, they travel towards each other and meet in 3 Hrs. 1 car travels 1 MPH faster than the other. What is average speed of each car?
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\n" ); document.write( "Car 1 DATA:
\n" ); document.write( "time = 3 hrs ; distance = x miles ; rate = x/3 mph
\n" ); document.write( "---
\n" ); document.write( "Car 2 DATA:
\n" ); document.write( "time = 3 hrs ; distance = 261-x miles ; rate = (261-x)/3 mph
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\n" ); document.write( "Equation:
\n" ); document.write( "Car 1 rate - Car 2 rate = 1 mph
\n" ); document.write( "x/3 - (261-x)/3 = 1
\n" ); document.write( "----
\n" ); document.write( "Multiply thru by 3 to get:
\n" ); document.write( "x -(261-x) = 3
\n" ); document.write( "2x = 3+261
\n" ); document.write( "2x = 264
\n" ); document.write( "x = 132
\n" ); document.write( "261-x = 129
\n" ); document.write( "--
\n" ); document.write( "Car 1 rate: 132/3 = 44 mph
\n" ); document.write( "Car 2 rate: 129/3 = 43 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "Car 2 rate:
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