document.write( "Question 574257: A number is 6 times bigger than anather number. Calculate the values of the numbers if their differences is 12. \n" ); document.write( "
Algebra.Com's Answer #369004 by bucky(2189)\"\" \"About 
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Let x be the bigger number and y be the smaller number.
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\n" ); document.write( "You are told that x (the bigger number) is 6 times y (the smaller number). Therefore we can write the equation:
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\n" ); document.write( "x = 6y
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\n" ); document.write( "Then you are told that the difference between the two numbers is 12. That means that if you subtract y from x, the answer is 12. In equation form this is:
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\n" ); document.write( "x - y = 12
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\n" ); document.write( "But from the first equation, you know that x is equal to 6y. Therefore, in the second equation you can replace x with its equal 6y and this changes the second equation to:
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\n" ); document.write( "6y - y = 12
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\n" ); document.write( "Do the subtraction on the left side and you have:
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\n" ); document.write( "5y = 12
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\n" ); document.write( "Solve for y by dividing both sides of this equation by 5 and you get:
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\n" ); document.write( "y = 12/5
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\n" ); document.write( "And when you divide 5 into 12 you get 2.4 So you know that y, which is the smaller number, equals 2.4 And x, the larger number, equals 6 times y or 6 times 2.4 Multiply 6 times 2.4 and you get 14.4
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\n" ); document.write( "The two numbers are 14.4 and 2.4
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\n" ); document.write( "Check by subtracting the two numbers and you find that the difference is 12, just as the problem says it should be. And when you multiply 6 times the smaller number (6 times 2.4) you get 14.4 So the larger number (14.4) is 6 times the smaller number (2.4) which is also just as the problem says it should be.
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\n" ); document.write( "I hope this helps you to understand the problem a little better and that you can understand a process showing how the problem can be solved.
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