document.write( "Question 574176: A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE \n" ); document.write( "
Algebra.Com's Answer #368996 by stanbon(75887)\"\" \"About 
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A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.40x + 0.25(50-x) = 0.27*50
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40x + 25*50 - 25x = 27*50
\n" ); document.write( "15x = 2*50
\n" ); document.write( "x = 100/15 = 6 2/3 liters (amt. of 40% solution needed)
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\n" ); document.write( "50-x = 43 1/3 liters (amt. of 25% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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