document.write( "Question 574176: A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE \n" ); document.write( "
Algebra.Com's Answer #368996 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.40x + 0.25(50-x) = 0.27*50 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40x + 25*50 - 25x = 27*50 \n" ); document.write( "15x = 2*50 \n" ); document.write( "x = 100/15 = 6 2/3 liters (amt. of 40% solution needed) \n" ); document.write( "----- \n" ); document.write( "50-x = 43 1/3 liters (amt. of 25% solution needed) \n" ); document.write( "================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |