document.write( "Question 54595: How do I find \"all real zeros\" of the function?\r
\n" ); document.write( "\n" ); document.write( "f(x) = x^3-3x^2-x+3 \n" ); document.write( "

Algebra.Com's Answer #36896 by psbhowmick(878) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"f%28x%29+=+x%5E3-3x%5E2-x%2B3\"$
\n" ); document.write( " $\"f%28x%29+=+x%5E2%28x-3%29-%28x-3%29\"$
\n" ); document.write( " $\"f%28x%29+=+%28x%5E2-1%29%28x-3%29\"$
\n" ); document.write( " $\"f%28x%29+=+%28x%2B1%29%28x-1%29%28x-3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Thus f(x) becomes zero when x = -1,1,3. Hence f(-1), f(1), f(3) are the zeros. \n" ); document.write( "

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