document.write( "Question 573951: How to factor 14k^2-25k-84 completely
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Algebra.Com's Answer #368927 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Unwrap the FOIL.\r
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\n" ); document.write( "\n" ); document.write( "There are only a couple of ways to make

out of two factors each of which has an

; either

and

.\r
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\n" ); document.write( "\n" ); document.write( "So start with\r
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\r
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\n" ); document.write( "\n" ); document.write( "and mess about with various integer factors of 84, 84 and 1, 42 and 2, 21 and 3, 14 and 6, or 7 and 12. Nothing seems to work.\r
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\n" ); document.write( "\n" ); document.write( "So try\r
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\r
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\n" ); document.write( "\n" ); document.write( "with all of those factors of 84. Hmm...2 times 12 is 24 and -7 times 7 is -49 and 25 - 49 is -25. That looks promising. Let me know what you figured out.
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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