document.write( "Question 573760: Please Help. I am stuck on how to write out this problem.\r
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document.write( "If $ 2500 is invested in an account that pays interest compounded continuously, how long will it take to grow to $ 5000 at 4%? Round to the nearest tenth \n" );
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Algebra.Com's Answer #368905 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If $ 2500 is invested in an account that pays interest compounded continuously, how long will it take to grow to $ 5000 at 4%? \n" ); document.write( " Round to the nearest tenth \n" ); document.write( ": \n" ); document.write( "The continuous compound interest formula: \n" ); document.write( "A = amt after t time ($5000) \n" ); document.write( "P = initial principal ($2500) \n" ); document.write( "r = interest rate in decimal form (.04) \n" ); document.write( "t = time in yrs \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "divide both sides by 2500 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "use natural logs here \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "The log equiv of exponents \n" ); document.write( ".04t*ln(e)= ln(2) \n" ); document.write( ": \n" ); document.write( "the ln of e = 1, find ln of 2; therefore we have \n" ); document.write( ".04t = .693 \n" ); document.write( "t = \n" ); document.write( "t = 17.325 ~ 17.3 yrs \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this on your calc, enter: 2500*e^(.04*17.325); results: 4999.3 ~ 5000 \n" ); document.write( " \n" ); document.write( " |