document.write( "Question 573760: Please Help. I am stuck on how to write out this problem.\r
\n" ); document.write( "\n" ); document.write( "If $ 2500 is invested in an account that pays interest compounded continuously, how long will it take to grow to $ 5000 at 4%? Round to the nearest tenth
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Algebra.Com's Answer #368905 by ankor@dixie-net.com(22740)\"\" \"About 
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If $ 2500 is invested in an account that pays interest compounded continuously, how long will it take to grow to $ 5000 at 4%?
\n" ); document.write( " Round to the nearest tenth
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\n" ); document.write( "The continuous compound interest formula: \"A+=+P%2Ae%5E%28rt%29\", where
\n" ); document.write( "A = amt after t time ($5000)
\n" ); document.write( "P = initial principal ($2500)
\n" ); document.write( "r = interest rate in decimal form (.04)
\n" ); document.write( "t = time in yrs
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\n" ); document.write( "\"2500%2Ae%5E%28.04t%29+=+5000\"
\n" ); document.write( "divide both sides by 2500
\n" ); document.write( "\"e%5E%28.04t%29+=+5000%2F2500\"
\n" ); document.write( "\"e%5E%28.04t%29\" = 2
\n" ); document.write( "use natural logs here
\n" ); document.write( "\"ln%28e%5E%28.04t%29%29\" = ln(2)
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\n" ); document.write( "The log equiv of exponents
\n" ); document.write( ".04t*ln(e)= ln(2)
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\n" ); document.write( "the ln of e = 1, find ln of 2; therefore we have
\n" ); document.write( ".04t = .693
\n" ); document.write( "t = \".693%2F.04\"
\n" ); document.write( "t = 17.325 ~ 17.3 yrs
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\n" ); document.write( "Check this on your calc, enter: 2500*e^(.04*17.325); results: 4999.3 ~ 5000
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