document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54644>Question 54644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> identify the center of the circle (x+2)^2+(y-1)^2=9  I got -1,1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36890 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The centre of the circle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B2%29%5E2%2B%28y-1%29%5E2=9 ALIGN=MIDDLE  ALT=\"%28x%2B2%29%5E2%2B%28y-1%29%5E2=9\"   DISABLED_style= \"max-width:90%; height:auto;\" > is is (-2,1) and not (-1,1). </SPAN>\n" );
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