document.write( "Question 573849: What are the following triangles with these lengths for sides? Are they right triangles, acute triangles, or obtuse triangles?\r
\n" ); document.write( "\n" ); document.write( "3, 4, 5
\n" ); document.write( "5, 8, 10
\n" ); document.write( "3, 4, 6
\n" ); document.write( "3, 5, 8
\n" ); document.write( "4, 5, 8
\n" ); document.write( "4, 5, 10
\n" ); document.write( "6, 8, 10
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Algebra.Com's Answer #368898 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "First check to see if you have a triangle at all. Add the two short dimensions. If the sum is STRICTLY GREATER THAN the long side, then you have a triangle and you can proceed. (If the sum of the two short sides is equal to the third side, then you have a straight line -- not a triangle. If the sum of the two short sides is less than the third side, then you have two short sides flapping around unable to meet in a third vertex.)\r
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\n" ); document.write( "\n" ); document.write( "Square the measures of each of the sides and then sum the squares of the two short sides.\r
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\n" ); document.write( "\n" ); document.write( "If the sum is equal to the square of the long side, then you have a right triangle.\r
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\n" ); document.write( "\n" ); document.write( "If the sum is less than the square of the long side, then you have an obtuse triangle.\r
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\n" ); document.write( "\n" ); document.write( "If the sum is greater than the square of the long side, then you have an acute triangle.\r
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\n" ); document.write( "\n" ); document.write( "Example: 3, 4, 6: 3 + 4 = 7 > 6, hence a triangle. 3 squared is 9, 4 squared is 16. 9 plus 16 is less than 6 squared (36), so you have an obtuse triangle.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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