document.write( "Question 573813: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 mph and train B is traveling at 48 mph. Train A passes the station at 7:15 pm. If train B passes at 7:30pm, at what time would train B catch up to train A?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "I know this is not that complicated, but for some reason I am drawing a blank on how to solve this. Really would appreciate any help. \n" );
document.write( "
Algebra.Com's Answer #368865 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 mph and train B is traveling at 48 mph. Train A passes the station at 7:15 pm. If train B passes at 7:30pm, at what time would train B catch up to train A? \n" ); document.write( "----------------------------- \n" ); document.write( "Train A DATA: \n" ); document.write( "rate = 40 mph; distance = x miles ; time = d/r = x/40 hrs \n" ); document.write( "------- \n" ); document.write( "Train B DATA: \n" ); document.write( "rate = 48 mph ; distance = x miles ; time = d/r = x/48 hrs \n" ); document.write( "------ \n" ); document.write( "Eqaution: \n" ); document.write( "A time - B time = 1/4 hr \n" ); document.write( "(x/40) - (x/48) = 1/4 hr \n" ); document.write( "-------- \n" ); document.write( "[48x - 40x)/(40*48) = 1/4 \n" ); document.write( "---- \n" ); document.write( "8x = 10*48 \n" ); document.write( "x = 10*6 \n" ); document.write( "x = 60 miles \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |